Q1:100∠0° * 3 / (3+J4) = 36 - J48 ?
=(100+0j)*3(3-4j)/(3+4j)(3-4j)
=100*3(3-4j)/(9+16)
=300(3-4j)/25
=3*4(3-4j)
=12(3-4j)
=34-48j
Q2:極座標換成直角座標: 100∠-60° = 100 - J100√3 ?
=100(cos-60+jsin-60)
=100(cos60-jsin60)
=100(sin30-jsin60)
=100(1/2-√3j/2)
=50(1-√3j)
=50-50√3j
=(50,-50√3)
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